Viết cadc phương trình hóa học để hoàn thành dãy chuyển hóa học sau :
a, \(NaCl\rightarrow Cl_2\rightarrow HCl\rightarrow FeCl_2\rightarrow FeCl_3\)
b, \(C\rightarrow CO\rightarrow CO_2\rightarrow K_2CO_3\rightarrow KHCO_3\)
K
Khách
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Những câu hỏi liên quan
DH
24 tháng 2 2019
Tự cân bằng nhá!
a,
\(HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\
Cl_2+Fe\rightarrow FeCl_3\\
FeCl_3+NaOH\rightarrow Fe\left(OH\right)_3+NaCl\\
NaCl+H_2SO_{4\left(dn\right)}\rightarrow Na_2SO_4+HCl\\
HCl+CuO\rightarrow CuCl_2+H_2O\\
CuCl_2+AgNO_3\rightarrow Cu\left(NO_3\right)_2+AgCl\)
b,
\(KMnO_4+HCl\rightarrow KCl+MnCl_2+Cl_2+H_2O\\ Cl_2+H_2\rightarrow HCl\\ HCl+Fe\left(OH\right)_3\rightarrow FeCl_3+H_2O\\ FeCl_3+AgNO_3\rightarrow Fe\left(NO_3\right)_3+AgCl\\ AgCl-as,t^o->Ag+Cl_2\\ Cl_2+NaBr\rightarrow NaCl+Br_2\\ Br_2+NaI\rightarrow NaBr+I_2\)
c, Giống câu b 3 pt đầu
\(HCl+Fe\left(OH\right)_2\rightarrow FeCl_2+H_2O\\
FeCl_2+AgNO_3\rightarrow Fe\left(NO_3\right)_2+AgCl\\
AgCl-as,t^o->Ag+Cl_2\)
d,
\(HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\
Cl_2+Fe\rightarrow FeCl_3\\
FeCl_3+NaOH\rightarrow Fe\left(OH\right)_3+NaCl\\
Fe\left(OH\right)_3+H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+H_2O\)
e,
\(HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\
Cl_2+NaOH\rightarrow NaCl+NaClO+H_2O\\
NaCl+H_2SO_{4\left(dn\right)}\rightarrow Na_2SO_4+HCl\\
CuO+HCl\rightarrow CuCl_2+H_2O\\
CuCl_2+AgNO_3\rightarrow Cu\left(NO_3\right)_2+AgCl\\
AgCl-as,t^o->Ag+Cl_2\)
f,
\(MnO_2+HCl\rightarrow MnCl_2+Cl_2+H_2O\\ Cl_2+KOH-t^o->KClO_3+KCl+H_2O\\ KClO_3\rightarrow KCl+O_2\\ KCl+H_2SO_{4\left(dn\right)}\rightarrow K_2SO_4+HCl\\ HCl+MnO_2\rightarrow MnCl_2+Cl_2+H_2O\\ Ca\left(OH\right)_2+Cl_2\rightarrow CaCl_2+Ca\left(ClO\right)_2+H_2O\)
DC
11 tháng 3 2020
1/
MnO2+ 4HCl\(\rightarrow\) MnCl2+ Cl2+ 2H2O
Cl2+H2\(\xrightarrow[]{as}\) 2HCl
HCl+ NaOH\(\rightarrow\) NaCl+ H2O
2NaCl\(\xrightarrow[]{đpnc}\) 2Na+ Cl2
Cl2+ SO2+ 2H2O\(\rightarrow\) H2SO4+ 2HCl
H2SO4 đặc+ NaCltinh thể\(\xrightarrow[]{< 250\cdot C}\) NaHSO4+ HCl
4/
H2SO4 đặc+ NaCltinh thể\(\xrightarrow[]{< 250\cdot C}\) NaHSO4+ HCl
MnO2+ 4HCl\(\rightarrow\) MnCl2+ Cl2+ 2H2O
3Cl2+ 6KOHđặc\(\rightarrow\) KClO3+ 5KCl+ 3H2O
2KClO3\(\xrightarrow[MnO2]{to}\) 2KCl+ 3O2
2KCl\(\xrightarrow[]{đpnc}\) K+ Cl2
Cl2+ Ca(OH)2\(\xrightarrow[]{30\cdot C}\) CaOCl2+ H2O
HA
11 tháng 3 2020
1, \(MnO_2+4HCl\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
\(Cl_2+H_2\underrightarrow{as,t^o}2HCl\)
\(HCl+NaOH\rightarrow NaCl+H_2O\)
\(2NaCl+2H_2O\xrightarrow[cmn]{đpdd}2NaOH+Cl_2+H_2\)
\(4Cl_2+4H_2O+H_2S\rightarrow H_2SO_4+8HCl\)
\(H_2SO_4+NaCl\underrightarrow{>400^oC}Na_2SO_4+HCl\uparrow\)
2, \(2KMnO_4+18HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(3Cl_2+2Fe\underrightarrow{t^o}2FeCl_3\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3\downarrow+3KCl\)
\(2KCl+2H_2O\xrightarrow[cmn]{đpdd}2KOH+Cl_2+H_2\)
3, \(4HCl+MnO_2\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
\(3Cl_2+2Fe\underrightarrow{t^o}2FeCl_3\)\(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_3\downarrow\)
\(2NaCl+H_2SO_4\underrightarrow{>400^oC}Na_2SO_4+2HCl\)
\(2HCl+Cu\left(OH\right)_2\rightarrow CuCl_2+2H_2O\)
\(CuCl_2+2AgNO_3\rightarrow Cu\left(NO_3\right)_2+2AgCl\downarrow\)
4, \(H_2SO_4+2NaCl\underrightarrow{>400^oC}Na_2SO_4+2HCl\uparrow\)
\(4HCl+MnO_2\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)
\(3Cl_2+6KOH\underrightarrow{80-100^oC}5KCl+KClO_3+3H_2O\)
\(2KClO_3\underrightarrow{t^o}2KCl+3O_2\)
\(2KCl+2H_2O\xrightarrow[cmn]{đpdd}2KOH+Cl_2+H_2\)
\(Cl_2+Ca\left(OH\right)_2\underrightarrow{30^oC}CaOCl_2+H_2O\)
Bạn tham khảo nhé!
16 tháng 3 2022
CH4 + 2O2 -> (t°) CO2 + 2H2O
C2H2 + 2Br2 -> C2H2Br4
CH4 + Cl2 -> (askt) CH3Cl + HCl
2C2H2 + 5O2 -> (t°) 4CO2 + 2H2O
C2H4 + Br2 -> C2H4Br2
nCH2=CH2 -> (t°, p, xt) n(-CH2-CH2-)
C2H4 + 3O2 -> (t°) 2CO2 + 2H2O
1 tháng 8 2019
a) 2FeCl2 + Cl2 \(\underrightarrow{to}\) 2FeCl3
b) Al2O3 + 6HCl → 2AlCl3 + 3H2O
c) 3KOH + H3PO4 → K3PO4 + 3H2O
d) 4CO + Fe3O4 \(\underrightarrow{to}\) 3Fe + 4CO2
e) 3Cl2 + 6KOH → 5KCl + KClO3 + 3H2O
g) 4Zn + 5H2SO4 → 4ZnSO4 + H2S + 4H2O
16 tháng 10 2018
a, SO2 + \(\dfrac{1}{2}\)O2 -> SO3
b. Fe(OH)2 + 2HCl -> FeCl2 + 2H2O
c, BaCl2 + Na2SO4 -> BaSO4 + 2NaCl
d, Fe3O4 + 8HCl -> FeCl2 + 2FeCl3 + 4H2O
17 tháng 10 2018
a) 2SO2 + O2 →to 2SO3
b) Fe(OH)2 + 2HCl → FeCl2 + 2H2O
c) BaCl2 + Na2SO4 → BaSO4↓ + 2NaCl
d) Fe3O4 + 8HCl → FeCl2 + 2FeCl3 + 4H2O
QN
9 tháng 5 2021
\(2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O\)
\(H_2S+4Br_2+4H_2O\rightarrow8HBr+H_2SO_4\)
\(NaCl+AgNO_3\rightarrow AgCl+NaNO_3\)
27 tháng 4 2022
\(1,CH_4+Cl_2\underrightarrow{\text{ánh sáng}}CH_3Cl\\ 2,C_6H_6+Br_2\xrightarrow[t^o]{Fe}C_6H_5Br\\ 3,C_6H_6+Cl_2\underrightarrow{\text{ánh sáng}}C_6H_5Cl\\ 4,2CH_3COOH+CaCO_3\rightarrow\left(CH_3COO\right)_2Ca+CO_2\uparrow+H_2O\\ 5,\left(RCOO\right)_3C_3H_5+3NaOH\rightarrow3RCOONa+C_3H_5\left(OH\right)_3\\ 6,CaCO_3+CO_2+H_2O\rightarrow Ca\left(HCO_3\right)_2\\ 7,2NaHCO_3\underrightarrow{t^o}Na_2CO_3+CO_2\uparrow+H_2O\\ 8,NaOH+SiO_2\underrightarrow{t^o}Na_2SiO_3+H_2O\)
\(9,NaHCO_3+HCl\rightarrow NaCl+CO_2\uparrow+H_2O\\ 10,Cl_2+H_2O⇌HCl+HClO\\ 11,CH_3COOC_2H_5+NaOH\rightarrow CH_3COONa+C_2H_5OH\\ 12,C_6H_6+3H_2\xrightarrow[t^o]{Ni}C_6H_{12}\\ 13,\left(RCOO\right)_3C_3H_5+3H_2O\rightarrow3RCOOH+C_3H_5\left(OH\right)_3\\ 14,\left(-C_6H_{10}O_5-\right)_n+nH_2O\rightarrow nC_6H_{12}O_6\\ 15,CH_3COONa+NaOH\underrightarrow{t^o}CH_4\uparrow+Na_2CO_3\\16, Ca\left(HCO_3\right)\underrightarrow{t^o}CaCO_3+CO_2\uparrow+H_2O\)
\(17,MnO_2+4HCl\rightarrow MnCl_2+Cl_2\uparrow+2H_2O\\ 18,NaHCO_3+NaOH\rightarrow Na_2CO_3+H_2O\\ 19,2C_4H_{10}+5O_2\xrightarrow[men,xt]{t^o}4CH_3COOH+2H_2O\\ 20,2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O\\ 21,CH_3COOC_2H_5+H_2O\underrightarrow{t^o}CH_3COOH+C_2H_5OH\)
20 tháng 10 2018
1) 2CnH2n+3nO2→2nCO2+2nH2O
2) CnH2n + 2 + \(\dfrac{3n+1}{2}\) O2 -> nCO2 + (n+1)H2O.
3) CnH2n – 2 + \(\dfrac{3n-1}{2}\) O2 -> nCO2 +(n-1) H2O.
4) CnH2n-6 +\(\dfrac{3n-3}{2}\) O2 -> nCO2 + (n-3) H2O
20 tháng 10 2018
5) CnH2n+2O+\(\dfrac{3n}{2}\)O2→nCO2+(n+1)H2O
6) 2CxHyOz + \(\dfrac{4x+y-2z}{2}\) O2 →2x CO2 + yH2O
7) CxHyOzNt + \(\left(x+\dfrac{y}{4}\right)-\dfrac{z}{2}\)O2→xCO2+\(\dfrac{y}{2}\)H2O + \(\dfrac{t}{2}\) N2
a) 2NaCl----->2Na+Cl2
Cl2+H2--->2HCl
Fe+2HCl---->FeCl2+H2
2FeCl2+Cl2--->2FeCl3
b) C+CO2---->2CO
2CO+O2--->2CO2
CO2+2KOH--->K2CO3+H2O
K2CO3+CO2+H2O----.2KHCO3